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Probability Axioms & Events

Probability & Statistics • Topic 2

🧠 What actually is it?

Probability theory is the mathematical framework for quantifying uncertainty. In 1933, Andrey Kolmogorov established the foundations of modern probability using three simple axioms.

1. The 3 Axioms of Probability

  • Non-negativity: For any event $A$, the probability is non-negative:

    $$P(A) \ge 0$$

  • Certainty: The probability of the entire sample space $S$ (all possible outcomes) is 1:

    $$P(S) = 1$$

  • Additivity: For any two mutually exclusive (disjoint) events $A$ and $B$:

    $$P(A \cup B) = P(A) + P(B)$$

2. Types of Events

  • Mutually Exclusive (Disjoint): Events that cannot happen at the same time. If $A$ happens, $B$ cannot.

    $$A \cap B = \emptyset \implies P(A \cap B) = 0$$

  • Independent: The occurrence of one event does not affect the probability of the other.

    $$P(A \cap B) = P(A) \times P(B)$$

💡 Why was it invented & why do we need it?

Before axioms, mathematicians defined probability as "favorable cases divided by total cases". This failed for infinite possibilities (e.g., "what is the probability a random real number is between 1 and 2?"). Axioms made probability rigorous and allowed the creation of modern statistics.

🚫 Mutually Exclusive: Tossing a Coin

A single coin toss can land on Heads ($H$) or Tails ($T$), but **not both**. Thus, $H$ and $T$ are mutually exclusive.

🎲 Independent: Two Separate Dice

Rolling a 6 on Die #1 does not change your chances of rolling a 6 on Die #2. The events are independent.

Why GATE DA needs this: In Machine Learning, conditional independence is the foundational assumption behind algorithms like **Naive Bayes** and **Bayesian Networks**. Understanding how these events overlap prevents models from making false logical assumptions.

🔬 Venn Diagram Visualizer

Toggle the event states and watch the Venn diagram and probability formulas calculate dynamically.

Sample Space $S$ ($P(S) = 1.0$)
A B
GATE DA Practice

📝 GATE Level Practice Question

Let $A$ and $B$ be two events in a sample space $S$ such that $P(A) = 0.6$ and $P(B) = 0.4$.

1. If $A$ and $B$ are independent, find $P(A \cup B)$ and $P(A \cap B)$.

2. If $A$ and $B$ are mutually exclusive, find $P(A \cup B)$ and $P(A \cap B)$.

💡 Reveal Step-by-Step Solution

Part 1: Independent Events

  • By definition of independence:

    $$P(A \cap B) = P(A) \times P(B) = 0.6 \times 0.4 = 0.24$$

  • Using the addition rule of probability:

    $$P(A \cup B) = P(A) + P(B) - P(A \cap B) = 0.6 + 0.4 - 0.24 = 0.76$$

Part 2: Mutually Exclusive Events

  • By definition, mutually exclusive events cannot overlap:

    $$P(A \cap B) = 0$$

  • Using the addition rule:

    $$P(A \cup B) = P(A) + P(B) - P(A \cap B) = 0.6 + 0.4 - 0 = 1.0$$